The MPI-Mainz UV/VIS Spectral Atlas

of Gaseous Molecules of Atmospheric Interest

www.uv-vis-spectral-atlas-mainz.org

Hannelore Keller-Rudek1, Geert K. Moortgat2, Rolf Sander2, Rüdiger Sörensen1

1Satellite Group

2Atmospheric Chemistry Division

Max-Planck Institute for Chemistry
Mainz, Germany


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When referring to the Spectral Atlas, please cite our publication:

Keller-Rudek, H., Moortgat, G. K., Sander, R., and Sörensen, R.: The MPI-Mainz UV/VIS spectral atlas of gaseous molecules of atmospheric interest, Earth Syst. Sci. Data, 5, 365–373, (2013), DOI: 10.5194/essd-5-365-2013


Cross Sections / Alcohols / C2H5OH / JPL-2019(2020)_295K_121.567-230nm(rec)

DATAFILE: C2H5OH_JPL-2019(2020)_295K_121.567-230nm(rec).txt
NAME: ethyl alcohol, ethanol
FORMULA: C2H5OH
AUTHOR(YEAR): JPL-2019(2020)
T: 295K
λ: 121.567-230nm(rec)
BIBLIOGRAPHY: J. B. Burkholder, S. P. Sander, J. Abbatt, J. R. Barker, C. Cappa, J. D. Crounse, T. S. Dibble, R. E. Huie, C. E. Kolb, M. J. Kurylo, V. L. Orkin, C. J. Percival, D. M. Wilmouth, and P. H. Wine, "Chemical Kinetics and Photochemical Data for Use in Atmospheric Studies, Evaluation No. 19", JPL Publication 19-5, Jet Propulsion Laboratory, Pasadena, 2019, http://jpldataeval.jpl.nasa.gov
COMMENTS: JPL-2019(2020) recommendation:

121.567 nm: average of

D.R. Salahub and C. Sandorfy, "The far-ultraviolet spectra of some simple alcohols and fluoroalcohols", Chem. Phys. Lett. 8, 71-74 (1971); DOI: 10.1016/0009-2614(71)80578-X, and

C. Han, M. Suto, and L.C. Lee, "Fluorescence from photoexcitation of C2H5OH by vacuum ultraviolet radiation", J. Quant. Spectrosc. Radiat. Transfer 42, 557-562 (1989); DOI: 10.1016/0022-4073(89)90046-0

165–216 nm: data at 1-nm intervals of

V.L. Orkin, V. G. Khamaganov, L.E Martynova, and M.J. Kurylo, "High-accuracy measurements of OH* reaction rate constants and IR and UV absorption spectra: Ethanol and partially fluorinated ethyl alcohols", J. Phys. Chem. A 115, 8656-8668 (2011); DOI: 10.1021/jp202099t

220–230 nm: extrapolation of the data of Orkin et al., log σ(λ) = 11.1187 – 0.15069 λ

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